0=12x^2-68

Solution for 0=12x^2-68 equation:

0=12x^2-68

We move all terms to the left:

0-(12x^2-68)=0

We add all the numbers together, and all the variables

-(12x^2-68)=0

We get rid of parentheses

-12x^2+68=0

a = -12; b = 0; c = +68;
Δ = b2-4ac
Δ = 02-4·(-12)·68
Δ = 3264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3264}=\sqrt{64*51}=\sqrt{64}*\sqrt{51}=8\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{51}}{2*-12}=\frac{0-8\sqrt{51}}{-24}
=-\frac{8\sqrt{51}}{-24}
=-\frac{\sqrt{51}}{-3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{51}}{2*-12}=\frac{0+8\sqrt{51}}{-24}
=\frac{8\sqrt{51}}{-24}
=\frac{\sqrt{51}}{-3}
$